Consider the vector field [math].
Show that [math] is a flowline for the vector field [math].
That is, verify that (I trust you here)
[math] , , [math].

Now consider the curve [math]. It is not a flowline of the vector field [math], but of a vector field [math] which differs in definition from [math] only slightly.
[math] , , [math].

Your overall score for this problem is