If $f(x) = \frac{x^{3}+6}{5}$ then $\frac{df}{dx} =$
The slope of the tangent line to $f$ at $x = 5$ is
If $T(t) = \frac{t^{3}+6}{5}$ is the temperature of a runner (in Celsius) at time t (in hours) find the rate at which the runners temperature is changing at time $t = 10$ with units: