Use local linearization to approximate $\sqrt {25.3}$ as follows:

Let $f(x) = \sqrt x$. The local linearization of $f$ at $25$ is $l_{25}(x) = y_0 + m(x-25)$,
where $m =$ and $y_0 =$

Using this, we find our approximation $\sqrt {25.3} \approx l_{25}(25.3) =$
NOTE: For this part, use fractions or give your approximation to at least 9 significant figures.