Let $V={\mathbb R}^2$. For $(u_1,u_2),(v_1,v_2) \in V$ and $a\in{\mathbb R}$ define vector addition by $(u_1,u_2) \boxplus (v_1,v_2) := (u_1+v_1 + 2,u_2+v_2-1)$ and scalar multiplication by $a \boxdot (u_1,u_2) := (au_1 + 2a - 2,au_2-a+1)$. It can be shown that $(V,\boxplus,\boxdot)$ is a vector space over the scalar field $\mathbb R$. Find the following:

the sum:

$(-6,-2)\boxplus (5,2) =$( , )

the scalar multiple:

$-2\boxdot (-6,-2) =$( , )

the zero vector:

$\underline{0}_V =$( , )

the additive inverse of $( x,y)$:

$\boxminus (x,y)=$( , )