Let $f(x) =\frac{10}{x}$
The slope of the tangent line to the graph of $f(x)$ at the point $(-3,-\frac{10}{3})$ is .
The equation of the tangent line to the graph of $f(x)$ at $(-3,-\frac{10}{3})$ is $y=mx+b$ for
$m=$
and
$b=$ .
Hint: the slope is given by the derivative at $x=-3$, ie.
$\displaystyle{ \lim_{x\to-3}\frac{f(-3+h)-f(-3)}{h}}$