Let $h(x) = 6-4x^{3}$,

$h'( 2 ) =$

Use this to find the equation of the tangent line to the curve $y = 6-4x^{3}$ at the point $( 2 , -26 )$ and write your answer in the form:

$y = mx+b$, where $m$ is the slope and $b$ is the y-intercept.

Your overall score for this problem is