Given that $f$, $g$, and $h$ are functions with values $f(2) = -3$, $g(2) = 1$, and $h(2) = -3$, and point-derivatives $f'(2) = 3$, $g'(2) = 5$, and $h'(2) = -3$, calculate the following.

1. $(3f+4h)'(2)$
2. $(2f+ 4 g - h)'(2)$
3. $(fh)'(2)$
4. $\displaystyle h(x) =\left( \frac{f}{g}\right)'(2)$