Fill in the table and guess the value of the limit:
$\lim\limits_{x \to 2} f(x)$, where $f(x)= \frac {x^3 - 8} {x^2 - 4}$

 $x$ $f(x)$ $x$ $f(x)$ 2.002 $\qquad \qquad$ 1.998 $\qquad \qquad$ 2.001 $\qquad \qquad$ 1.999 $\qquad \qquad$ 2.0005 $\qquad \qquad$ 1.9995 $\qquad \qquad$ 2.0001 $\qquad \qquad$ 1.9999 $\qquad \qquad$

The limit as $x \to 2$ is